Rotary Engines

flimper

Veteran
 Hampshire
Just watching the Wheeler Dealer episode with the Mazda RX-7, Ed said that the engine is not really a 1.3 but more like a 3.9 due to having 3 chambers not 1. Is this true and can somebody expand on this? Certainly explains the poor MPG on this and the RX-8.
 
Its been years since I looked at these, but I always though it was a 1.3 x 2 because of its twin rotors, i.e 1.3 per rotor. So really more like a 2.6. Even at that the fuel economy is still really poor and the torque is none existent. The final nail in their coffin for many was they need rebuilding far far to frequently. To the point where alot of UK warranty companies refused to cover them.
 
Never heard of it being described as 3.9

As far as I understand you have the inlet chamber, combustion chamber and then exhaust chamber. There are two of these so gives it the commonly listed 2.6ltr description. Though I could have this all wrong?
 
I'll try

In a conventional inline 4 of say 2.0 litres you will have four combustion chamber each with an effective capacity of 500cc. Each chamber produces one expansion stroke per revolution of the engine

In a rotary with a 'triangular' rotor (piston) oscillating inside an approximately 8 shaped chamber you have three expansion strokes per revolution. So a twin rotor with a notional 650cc combustion chamber will have an effective cc of 650x3x2. Which is 3.9 litres.

It's not usually expressed in this way but the logic is sound.
 
I remember a good few years ago I was looking at the rx8 in the mazda stealers (dreaming really cos I'd just passed my test) but the salesman told me it was 2x 0.65l engine section that made it up to 0.3 he could have been full of s**t though
 
I had a hi power rx8 in 2006, I believe it's because inside each chamber there are 3 separate chambers (inlet,compression,exhaust) as opposed to just one chamber on a conventional 4 stroke engine.
Instead of just measuring one of the chambers some people calculate the capacity by measuring all 3.
They then times this figure by 2 or 3 depending how many rotors the engine has, the same as you would by multiplying a normal engines combustion chamber capacity by the number if cylinders in the engine.
Rob
 
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